A) \[2560\text{ }N{{m}^{-2}}\]
B) \[3720\text{ }N{{m}^{-2}}\]
C) \[1208\text{ }N{{m}^{-2}}\]
D) \[10132\text{ }N{{m}^{-2}}\]
Correct Answer: A
Solution :
\[P=\frac{4T}{R}=\frac{4\times 1.6}{2.5\times {{10}^{-3}}}\] \[=2560N/{{m}^{2}}\]
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