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Manipal Medical Manipal Medical Solved Paper-2008

  • question_answer
    The Youngs. double slit experiment is performed with blue and with green light of wavelengths\[4360\overset{o}{\mathop{\text{A}}}\,\]and\[5460\overset{o}{\mathop{\text{A}}}\,\]respectively. If \[x\]is the distance of 4th maximum from the central one, then

    A) \[x\](blue) = \[x\] (green)

    B)  \[x\] (blue) > \[x\](green)

    C)  \[x\] (blue) < \[x\] (green)

    D)  \[\frac{x(blue)}{x(green)}=\frac{5460}{4360}\]

    Correct Answer: C

    Solution :

     Position of fourth maxima \[{{x}_{0}}=\frac{4D\lambda }{d}\] Or \[{{x}_{0}}\propto \lambda \] \[\therefore \] \[x(blue)>x(green)\]


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