A) \[{{10}^{10}}\]
B) \[{{10}^{20}}\]
C) \[{{10}^{30}}\]
D) \[{{10}^{40}}\]
Correct Answer: C
Solution :
\[n=\frac{P}{E}=\frac{P}{hv}=\frac{P\lambda }{hc}\] \[=\frac{1000\times 198.6}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\approx {{10}^{30}}\]
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