A) decrease by a factor\[\frac{2}{3}\]
B) decrease by a factor\[\frac{4}{9}\]
C) decrease by a factor\[\frac{5}{9}\]
D) decrease by a factor\[\frac{\sqrt{5}}{9}\]
Correct Answer: C
Solution :
Since, \[E=\Delta m{{c}^{2}}\Rightarrow E\propto {{c}^{2}}\] \[\therefore \] \[\frac{E-E}{E}=1{{\left( \frac{2}{3} \right)}^{2}}=\frac{5}{9}\]
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