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Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    A parallel beam of monochromatic light of wavelength 5000 A is incident normally on a single narrow slit of width 0.001 mm. The light is focused by a convex lens on a screen placed on the focal plane. The first minimum will be formed for the angle of diffraction equal to

    A)  \[0{}^\circ \]               

    B)  \[15{}^\circ \]

    C)  \[30{}^\circ \]            

    D)  \[60{}^\circ \]

    Correct Answer: C

    Solution :

    For the first minima\[d\sin \theta =\lambda \] \[\Rightarrow \] \[\sin \theta =\frac{\lambda }{d}\] \[\theta ={{\sin }^{-1}}\left[ \frac{5000\times {{10}^{-10}}}{0.001\times {{10}^{-3}}} \right]=30{}^\circ \]


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