A) \[1.5\times {{10}^{6}}\]
B) \[2.5\times {{10}^{6}}\]
C) \[3\times {{10}^{6}}\]
D) \[7.5\times {{10}^{6}}\]
Correct Answer: D
Solution :
\[E=\Delta m{{c}^{2}}\] \[E=\frac{0.3}{1000}\times {{(3\times {{10}^{8}})}^{2}}\] \[=2.7\times {{10}^{13}}J\] \[=\frac{2.7\times {{10}^{13}}}{3.6\times {{10}^{6}}}=7.5\times {{10}^{6}}kWh\]
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