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Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    The uncertainty in the position of an electron (mass\[9.1\times {{10}^{-28}}g\])moving with a velocity of \[3.0\times {{10}^{4}}cm\,{{s}^{-1}}\]accurate upto 0.011% will be

    A)  1.92 cm         

    B)  7.68 cm

    C)  0.175 cm        

    D)  3.84 cm

    Correct Answer: C

    Solution :

     \[\Delta x=\frac{h}{4\pi \times m\times \Delta v}\] \[=\frac{6.6\times {{10}^{-27}}\times 100}{4\times 3.14\times 9.1\times {{10}^{-28}}\times 3\times {{10}^{4}}\times 0.011}\] \[=0.175\,cm\]


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