A) \[1.0\times {{10}^{1}}\]
B) \[1.0\times {{10}^{30}}\]
C) \[1.0\times {{10}^{10}}\]
D) \[1.0\times {{10}^{5}}\]
Correct Answer: C
Solution :
At 298 K \[E{}^\circ =\frac{0.0591}{n}\log {{K}_{c}}\] \[0.591=\frac{0.0591}{1}\log {{K}_{c}}\] \[\log {{K}_{c}}=\frac{0.5910}{0.0591}\] \[\log {{K}_{c}}=10\] \[{{K}_{c}}={{10}^{10}}\]
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