A) \[5.33{}^\circ \]
B) \[4{}^\circ \]
C) \[2.6{}^\circ \]
D) \[3{}^\circ \]
Correct Answer: D
Solution :
For a thin prism, angle of minimum deviation is given by \[\delta =(\mu -1)A\] where,\[\mu \]is refractive index of the prism and A the angle of prism. For dispersion without deviation \[{{\delta }_{1}}={{\delta }_{2}}\] \[\Rightarrow \] \[({{\mu }_{1}}-1){{A}_{1}}=({{\mu }_{2}}-1){{A}_{2}}\] \[\Rightarrow \] \[{{A}_{2}}=\frac{({{\mu }_{1}}-1)}{({{\mu }_{2}}-1)}{{A}_{1}}\] Given, \[{{\mu }_{1}}=1.54,{{A}_{1}}=4{}^\circ ,{{\mu }_{2}}=1.72\] \[\Rightarrow \] \[{{A}_{2}}=\frac{(1.54-1)}{(1.72-1)}\times 4=3{}^\circ \]
You need to login to perform this action.
You will be redirected in
3 sec
