Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    1 N/m is equal to

    A)  \[1\,J{{m}^{-2}}\]         

    B)  \[1\,J{{m}^{3}}\]

    C)  \[1\,J{{m}^{2}}\]          

    D)  None of these

    Correct Answer: A

    Solution :

     Given, \[\frac{1\,newton}{metre}\] Or \[\frac{1\,newton-metre}{metr{{e}^{2}}}\] \[=\frac{force\times distance}{{{(distance)}^{2}}}=\frac{1\text{ }joule}{{{(metre)}^{2}}}\] \[\therefore \] \[N/m=1\text{ }J/{{m}^{2}}=1\text{ }J{{m}^{-2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner