A) 300
B) 500
C) 200
D) 100
Correct Answer: B
Solution :
The power gain is defined as the ratio of charge in output power to the charge in input power. Since, \[P=Vi\] Therefore, Power gain = current gain\[\times \]voltage gain \[=\beta \times \beta \left( \frac{{{R}_{out}}}{{{R}_{in}}} \right)\] \[={{\beta }^{2}}\left( \frac{{{R}_{out}}}{{{R}_{in}}} \right)\] Given,\[\beta =10,{{R}_{in}}=20\,k\Omega \]and \[{{R}_{out}}=100\,k\Omega \] \[\therefore \]Power gain \[={{(10)}^{2}}\left( \frac{100}{20} \right)\] \[=100\times 5\] \[=500\]
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