A) 0.5 g
B) 4g
C) 6 g
D) 8 g
Correct Answer: D
Solution :
Rate of diffusion \[=\frac{V}{t}\propto \frac{1}{\sqrt{m}}\] \[\Rightarrow \] \[\frac{{{r}_{{{H}_{2}}}}}{{{r}_{{{O}_{2}}}}}=\frac{{{V}_{{{H}_{2}}}}}{{{V}_{{{O}_{2}}}}}=\frac{{{n}_{{{H}_{2}}}}}{{{n}_{{{O}_{2}}}}}=\sqrt{\frac{{{M}_{{{O}_{2}}}}}{{{M}_{{{H}_{2}}}}}}\] \[\frac{2/2}{w/32}=\sqrt{\frac{32}{2}},\frac{32}{w}=4,w=8g\]
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