A) Geometrical
B) Optical
C) Linkage
D) lonisation
Correct Answer: D
Solution :
\[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]N{{O}_{2}}\]and\[[Co{{(N{{H}_{3}})}_{4}}ClN{{O}_{2}}]Cl\]give different ions when subjected to ionisation. Thus, these are ionisation isomers and they exhibit ionisation isomerism. \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]N{{O}_{2}}\to {{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}+NO_{2}^{-}\] \[[Co{{(N{{H}_{3}})}_{4}}ClN{{O}_{2}}]Cl\to {{[Co{{(N{{H}_{3}})}_{4}}ClN{{O}_{2}}]}^{+}}+C{{l}^{-}}\]
You need to login to perform this action.
You will be redirected in
3 sec
