Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    One-fourth length of a spring of force constant \[k\]is cut away. The force constant of the remaining spring will be

    A)  \[\frac{3}{4}k\]

    B)  \[\frac{4}{3}k\]

    C)  \[k\]

    D)  \[4k\]

    Correct Answer: B

    Solution :

     \[k\propto \frac{1}{l}\] Since, one-fourth length is cut away. So remaining length is\[\frac{3}{4}\]th, hence k become\[\frac{4}{3}\]times ie, \[k=\frac{4}{3}k\].


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