A) \[2\times {{10}^{12}}N\]
B) \[2\times {{10}^{11}}N\]
C) \[2\times {{10}^{10}}N\]
D) \[2\times {{10}^{6}}N\]
Correct Answer: D
Solution :
Youngs modulus of elasticity \[Y=\frac{FL}{Al}\] To double the length \[l=L\] \[\therefore \] \[Y=\frac{F}{A}\Rightarrow F=YA\] \[=2\times {{10}^{11}}\times 0.1\times {{10}^{-4}}=2\times {{10}^{6}}N\]
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