Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    A body starts to fall freely under gravity. The distances covered by it in first, second and third seconds are in ratio

    A)  \[1:3:5\]       

    B)  \[1:2:3\]

    C)  \[1:4:9\]       

    D)  \[1:5:6\]

    Correct Answer: A

    Solution :

     According to equation of motion, distance covered in nth sec. \[{{S}_{n}}=u=\frac{a}{2}(2n-1)\] \[{{S}_{n}}=\frac{a}{2}(2n-1)\] \[\therefore \] \[{{S}_{1}}:{{S}_{2}}:{{S}_{3}}\] \[=\{2(1)-1\}:\{2(2)-1\}:\{2(3)-1\}\] \[=1:3:5\]


You need to login to perform this action.
You will be redirected in 3 sec spinner