Manipal Medical Manipal Medical Solved Paper-2012

  • question_answer
    During an adiabatic process, the cube of the pressure is found to be inversely proportional to the fourth power of the volume. Then, the ratio of specific heats is

    A)  1                 

    B)  1.33

    C)  1.67              

    D)  1.4

    Correct Answer: B

    Solution :

     Equation of an adiabatic process is \[p{{V}^{\gamma }}=\]constant            ...(i) Given,        \[{{p}^{3}}=\frac{k}{{{V}^{4}}}\] \[{{p}^{3}}{{V}^{4}}=k\]           (constant) \[p{{V}^{4/3}}=k\]             ...(ii) Comparing Eqs. (i) and (ii), we get \[\gamma =\frac{4}{3}=1.33\]


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