A) \[A\]
B) \[{{A}^{3}}\]
C) \[\sqrt{A}\]
D) \[{{A}^{1/3}}\]
Correct Answer: A
Solution :
Radius of nucleus \[R={{R}_{0}}{{A}^{1/3}}\] where, \[{{R}_{0}}=1.2\times {{10}^{-15}}m\] Volume of nucleus\[(V)=\frac{4}{3}\pi {{R}^{3}}\] \[=\frac{4}{3}\pi {{[{{R}_{0}}{{A}^{1/3}}]}^{3}}\] \[=\frac{4}{3}\pi R_{0}^{3}A\] \[V\propto A\] (where, A = mass number of the nucleus)
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