A) \[\frac{GMm}{R}\]
B) \[-\frac{13GMm}{14R}\]
C) \[\frac{GMm}{7R}\]
D) \[\frac{GMm}{14R}\]
Correct Answer: B
Solution :
The energy of artificial satellite at the surface of the earth \[{{E}_{1}}=-\frac{GMm}{R}\] When the satellite is intended to move in a circular orbit of radius 7R, then energy of artificial satellite \[{{E}_{2}}=-\frac{1}{2}\frac{GMm}{7R}\] The minimum energy required \[E={{E}_{1}}-{{E}_{2}}\] \[=-\frac{GMm}{R}+\frac{1}{2}\left( \frac{GMm}{7R} \right)\] \[=\frac{-14GMm+GMm}{14R}\] \[=-\frac{13GMm}{14R}\]
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