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Manipal Medical Manipal Medical Solved Paper-2012

  • question_answer
    In the Youngs double slit experiment, intensities of black and bright fringes are 1 and 4 respectively, the ratio of amplitudes of sources will be

    A)  \[1:1\]           

    B)  \[1:2\]

    C)  \[3:1\]            

    D)  \[1:4\]

    Correct Answer: B

    Solution :

     \[E=k{{a}^{2}}\] \[\Rightarrow \] \[E\propto {{a}^{2}}\] Or \[\frac{a_{1}^{2}}{a_{2}^{2}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] \[=\frac{1}{4}\] Or \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{2}\]


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