A) \[3\beta -\]particles
B) \[2\beta -\]particles and 1\[\alpha -\]particle
C) \[2\beta -\]particles and 1\[\gamma -\]particle
D) \[2\beta -\]particles and 1\[\beta -\]particle
Correct Answer: B
Solution :
To form its own isotope atomic number (Z) should remain same. So, the emission of one a-particle and two\[\beta -\]particles will maintain the Z same. where,\[\alpha -\]particle\[{{=}_{2}}H{{e}^{4}};\beta -\]particle\[{{=}_{-1}}{{\beta }^{0}}\]
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