A) 1s and 1s
B) 1s and \[2{{p}_{x}}\]
C) \[2{{p}_{y}}\]and\[2{{p}_{y}}\]
D) 1s and 2s
Correct Answer: C
Solution :
\[2{{p}_{y}}\]and\[2{{p}_{y}}\]will not form a\[\sigma -\]bond because on taking x-axis as internuclear axis\[2{{p}_{y}}\]and\[2{{p}_{y}}\]orbitals overlap sideway (lateral overlapping) resulting in the formation of a \[\pi -\]bond.
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