Manipal Medical Manipal Medical Solved Paper-2012

  • question_answer
    138 g of ethyl alcohol is mixed with 72 g of water. The ratio of mole fraction of alcohol to water is

    A)  \[3:4\]           

    B)  \[1:2\]

    C)  \[1:4\]            

    D)  \[1:1\]

    Correct Answer: A

    Solution :

     Number of moles of \[{{C}_{2}}{{H}_{5}}OH=\frac{138}{46}=3\] Number of moles of\[{{H}_{2}}O=\frac{72}{18}=4\] Mole fraction, \[{{x}_{{{C}_{2}}{{H}_{5}}OH}}=\frac{3}{3+4}\] \[=\frac{3}{7}\] Mole fraction, \[{{x}_{{{H}_{2}}O}}=\frac{4}{3+7}=\frac{4}{7}\] \[\frac{{{x}_{{{C}_{2}}{{H}_{5}}OH}}}{{{x}_{{{H}_{2}}O}}}=\frac{3/7}{4/7}=\frac{3}{4}\]


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