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Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    A 600 kg rocket is set for vertical firing the exhaust speed is 800 m/s to given an initial upward acceleration of\[20\text{ }m/{{s}^{2}},\]the amount of gas ejected per second to supply. The needed thrust will be

    A)  \[137.5kg/s\]         

    B)  \[185.5kg/s\]

    C)  \[187.5kg/s\]         

    D)  \[127.5kg/s\]

    Correct Answer: C

    Solution :

     Using the relation \[\left[ \frac{\Delta m}{\Delta t} \right]v-mg=ma\] Or \[\frac{\Delta m}{\Delta t}\times (800)=m(g+a)\] Or \[800\times \frac{\Delta m}{\Delta t}\times 5000(10+20)\] Or \[\frac{\Delta m}{\Delta t}=\frac{5000\times 30}{800}\] Or \[\frac{\Delta m}{\Delta t}=\frac{1500}{8}=187.5\,kg/s\]


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