A) 317 m/s
B) 635 m/s
C) 830 m/s
D) 950 m/s
Correct Answer: B
Solution :
The volume of hydrogen and oxygen in a mixture is\[4:1\]. So let V be the volume of oxygen. The volume of hydrogen will be\[4V\]if\[{{\rho }_{m}}\]be the density of mixture, then \[{{\rho }_{m}}=\frac{4V\times 1+V\times 1\,s}{5m}=4\] \[V\propto {{\left( \frac{1}{\rho } \right)}^{1/2}}\] Velocity in mixture\[=\frac{1270}{{{(4)}^{3/2}}}=635\text{ }m/s\]
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