A) \[I<II<III\]
B) \[II<I<III\]
C) \[III<II<I\]
D) \[I<III<II\]
Correct Answer: C
Solution :
More the number of electron donating groups i.e.,\[C{{H}_{3}}\]at o-and p-position wrt\[Cl\]atom, Sess reactive is the compound, therefore, correct arranqement is\[III<II<I\].
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