A) \[AgCl{{O}_{4}}\]
B) \[A{{g}_{2}}S{{O}_{4}}\]
C) \[AgF\]
D) \[AgN{{O}_{3}}\]
Correct Answer: B
Solution :
The solubility of a compound depends upon its hydration enthalpy, if hydration enthalpy exceeds the lattice enthalpy than it is soluble in water. For\[A{{g}_{2}}S{{O}_{4}},\]hydration enthalpy is lower than lattice enthalpy. So, it is insoluble in water.
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