A) 1
B) 0.5
C) 2
D) 0.05
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{12}}{{O}_{6}}+6{{O}_{2}}\xrightarrow[{}]{{}}6C{{O}_{2}}+6{{H}_{2}}O\] \[RQ=\frac{Value\,of\,C{{O}_{2}}}{Volume\,of\,{{O}_{2}}}=\frac{6}{6}=1\]
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