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MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer
    If length of a simple pendulum increases by 300%, then its time period increases by

    A)  100%                                   

    B)  200%

    C)  300%                                   

    D)  400%

    Correct Answer: A

    Solution :

                    Time period\[{{T}_{1}}=2\pi \sqrt{\frac{l}{g}}\] If length is increased by 300%                 \[{{T}_{2}}=2\pi \sqrt{\frac{l+3l}{g}}\]                 \[{{T}_{2}}=2{{T}_{1}}\] % increase in time period \[=\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}}\times 100\] =100%


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