A) 1200 yr
B) 6400 yr
C) 1800 yr
D) 2200 yr
Correct Answer: B
Solution :
Remaining quantity \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{{{N}_{0}}}{16}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\therefore \] \[n=4\] \[\frac{t}{{{t}_{1/2}}}=4\] \[\Rightarrow \] \[t=4{{t}_{1/2}}=4\times 1600\] \[=6400yr\]
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