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MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer
    If distance between light source and screen is doubled, then intensity of light will become

    A)  half                                      

    B)  double

    C)  remains same  

    D)  1/4th

    Correct Answer: D

    Solution :

                    Intensity\[\propto \frac{1}{{{r}^{2}}}\] If distance is made double, then intensity becomes\[\frac{1}{4}th\].


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