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MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer
    The ionisation percentage of\[0.2\text{ }M\text{ }HCN\]the solution is 0.02%. What will be the value of ionisation constant?

    A)  \[8\times {{10}^{-5}}\]                                 

    B)  \[8\times {{10}^{-9}}\]

    C)  \[8\times {{10}^{-7}}\]                                 

    D)  \[8\times {{10}^{-3}}\]

    Correct Answer: A

    Solution :

                    \[{{K}_{h}}=C{{\alpha }^{2}}=0.2\times {{(0.02)}^{4}}\] \[=0.2\times 0.0004\]      \[=8\times {{10}^{-5}}\]


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