A) \[HCHO\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}COC{{H}_{3}}\]
D) \[{{C}_{6}}{{H}_{5}}OH\]
Correct Answer: A
Solution :
\[6HCHO+4N{{H}_{3}}\xrightarrow[{}]{{}}\underset{Urotropine}{\mathop{{{(C{{H}_{2}})}_{6}}{{N}_{4}}}}\,+6{{H}_{2}}O\]
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