A) 14 L
B) 4L
C) 8L
D) 12 L
Correct Answer: A
Solution :
\[2{{C}_{6}}{{H}_{6}}+7{{O}_{2}}\xrightarrow{{}}4C{{O}_{2}}+6{{H}_{2}}O\] \[2\times 22.4\text{ }L\] ethane required to complete burning =156.8\[{{O}_{2}}\]. \[4L=\frac{156.8}{2\times 22.4}\times 4\] \[=14L{{O}_{2}}\]
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