A) \[12.981\times {{10}^{2}}{{m}^{2}}\]
B) \[9.281\times {{10}^{9}}{{m}^{2}}\]
C) \[1.69\times {{10}^{12}}{{m}^{2}}\]
D) \[4.529\times {{10}^{9}}{{m}^{2}}\]
Correct Answer: C
Solution :
The capacitance of a parallel plate capacitor of area A and separation d between plates is \[C=\frac{{{\varepsilon }_{0}}A}{d}\] \[{{\varepsilon }_{0}}=8.854\times {{10}^{12}}{{C}^{2}}/N-{{m}^{2}}\] \[A=\frac{cd}{{{\varepsilon }_{0}}}=\frac{3\times 5\times {{10}^{-3}}}{8.854\times {{10}^{-12}}}\] \[=1.69\times {{10}^{12}}{{m}^{2}}\]
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