A) B/2
B) 2B
C) 0
D) 4B
Correct Answer: C
Solution :
Magnetic .field \[{{B}_{1}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{2i}{R}\] and \[{{B}_{2}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{4i}{R}\] \[{{B}_{2}}-{{B}_{1}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{2i}{R}=B\] \[{{B}_{2}}=2{{B}_{1}}\] \[2{{B}_{1}}-{{B}_{1}}=B\] \[{{B}_{1}}=B\]
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