A) 30kV
B) 50kV
C) 80RV
D) 60kV
Correct Answer: A
Solution :
\[\lambda =\frac{hc}{eV}\]\[V=\frac{hc}{e\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 0.4125\times {{10}^{-10}}}\] \[=30\times {{10}^{3}}V=30\,kV\]
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