MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    A monoatomic gas supplied the heat Q very slowly keeping the pressure constant. The work done by the gas will be

    A)  \[\frac{2}{3}Q\]                                              

    B)  \[\frac{3}{5}Q\]

    C)  \[\frac{2}{5}Q\]                                              

    D)  \[\frac{1}{5}Q\]

    Correct Answer: C

    Solution :

                    \[Q=n{{C}_{p}}\Delta T\] \[\frac{Q}{dU}=\frac{n{{C}_{P}}\Delta T}{n{{C}_{V}}\Delta T}=\frac{{{C}_{P}}}{{{C}_{V}}}=\gamma \]                 \[\gamma =\frac{5}{3}\]                 \[\frac{Q}{dU}=\frac{5}{3}\]                 \[dU=\frac{3}{5}Q\]                 \[Q=dU+W\]                 \[W=Q-dU\]                 \[=Q-\frac{3}{5}QW=\frac{2}{5}Q\]


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