A) Positorn
B) Proton
C) He
D) None of these
Correct Answer: A
Solution :
\[{{m}_{e}}=9.1\times {{10}^{31}}kg\] \[e=1.6\times {{10}^{-19}}C\] \[\frac{e}{m}=\frac{1.6\times {{10}^{-19}}}{9.1\times {{10}^{-31}}}=1.75\times {{10}^{11}}C/kg\] \[{{m}_{p}}=1.67\times {{10}^{-27}}kg\] \[e=1.6\times {{10}^{-19}}C\] \[\frac{e}{m}=\frac{1.6\times {{10}^{-19}}}{1.67\times {{10}^{-27}}}=9.58\times {{10}^{7}}C/kg\] \[{{m}_{He}}=6.6\times {{10}^{-27}}kg\] \[{{e}_{He}}=2\times 1.6\times {{10}^{-19}}C\] \[\frac{e}{m}=\frac{2\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-27}}}=4.87\times {{10}^{7}}C/kg\] Hence, positron has higher specific charge.
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