A) \[3.2\times {{10}^{-6}}\]per second
B) \[5\times {{10}^{17}}\]per second
C) \[2\times {{10}^{17}}\]per second
D) \[2\times {{10}^{18}}\]8 per second
Correct Answer: B
Solution :
\[E=hv\] \[v=\frac{E}{h}=\frac{2\times {{10}^{3}}\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}=9.84\times {{10}^{17}}\]\[=5\times {{10}^{17}}\]per second Since, energy\[\propto \]frequency higher the energy and higher the frequency.
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