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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    The crystal field splitting for\[C{{r}^{3+}}\]ion in an octahedral field increases for ligands \[{{I}^{-}},{{H}_{2}}O,\] \[N{{H}_{3}},C{{N}^{-}}\] and the order is

    A)  \[{{\text{I}}^{-}}<{{H}_{2}}O<N{{H}_{3}}<C{{N}^{-}}\]

    B)  \[C{{N}^{-}}<{{\text{I}}^{-}}<{{H}_{2}}O<N{{H}_{3}}\]

    C)  \[C{{N}^{-}}<N{{H}_{3}}<{{H}_{2}}O<{{I}^{-}}\]

    D)  \[N{{H}_{3}}<{{H}_{2}}O<{{I}^{-}}<C{{N}^{-}}\]

    Correct Answer: A

    Solution :

                    Crystal field splitting,\[{{\Delta }_{0}}\]depends upon the field produced by the ligand and charge on the metal ion. Order of increasing field strength of the given ligands are \[{{I}^{-}}<{{H}_{2}}O<N{{H}_{3}}<C{{N}^{-}}\]


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