question_answer

The correct set of quantum numbers for the unpaired electron of a chlorine atom is

A)  \[2,0,0,+\frac{1}{2}\]                    

B)  \[2,1,-1,+\frac{1}{2}\]

C)  \[3,1,-1,\pm \frac{1}{2}\]                           

D)  \[3,0,0,\pm \frac{1}{2}\]

Correct Answer: C

Solution :

                \[_{17}Cl=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{5}}\] \[\therefore \]One unpaired electron is present in 3p orbital. \[n=3\]                 \[l=1,\] \[m=-1,\]             \[s=\pm \frac{1}{2},\]