MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    Calculate the radius of a water molecule assuming to be spherical (density\[=1\text{ }g\text{ }m{{L}^{-1}}\]).

    A)  \[1.925\times {{10}^{-8}}cm\]                  

    B)  \[1.925\times {{10}^{-9}}cm\]

    C)  \[1.925\times {{10}^{-10}}cm\]                

    D)  \[1.925\times {{10}^{-11}}cm\]

    Correct Answer: A

    Solution :

                    Mass of one molecule \[=\frac{18}{6.02\times {{10}^{23}}}g\] Volume of one molecule                 \[=\frac{18g}{6.02\times {{10}^{23}}\times 1}\]                 \[=3.0\times {{10}^{-23}}\]                 \[\frac{4}{3}\pi {{r}^{3}}=3.0\times {{10}^{-23}}\]                 \[{{r}^{3}}=\frac{3\times 3.0\times {{10}^{-23}}\times 7}{4\times 22}\]                 \[r=1.925\times {{10}^{-8}}cm\]


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