MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    A galvanometer has a resistance of\[30\,\Omega \]. It gives full scale deflection with a current of 2mA. Calculate, the value of the resistance needed to convert it into an ammeter of range 0-0.3 A. The value of the resistance needed to convert galvanometer into ammeter

    A)  \[0.2\,\,\Omega \]                                        

    B)  \[0.3\,\,\Omega \]

    C)  \[0.4\,\,\Omega \]                        

    D)  \[0.52\,\,\Omega \]

    Correct Answer: A

    Solution :

                    Shunt\[S={{I}_{g}}G/I-{{I}_{g}},\]where\[{{I}_{g}}\]is range of galvanometer \[=2\text{ }mA\] Resistance of galvanometer\[G=30\,\Omega \] range of ammeter\[I=0.03\text{ }A\]                 \[S=\frac{{{I}_{g}}G}{I-{{I}_{g}}}=\frac{0.002\times 30}{0.03-0.002}=0.02\,\Omega \]


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