A) \[{{10}^{-4}}\text{ }M\text{ }AgN{{O}_{3}}and\text{ }{{10}^{-7}}M\text{ }HCl\]
B) \[{{10}^{-5}}\text{ }M\text{ }AgN{{O}_{3}}and\text{ }{{10}^{-6}}M\text{ }HCl\]
C) \[{{10}^{-5}}\text{ }M\text{ }AgN{{O}_{3}}and\text{ }{{10}^{-4}}M\text{ }HCl\]
D) \[{{10}^{-6}}\text{ }M\text{ }AgN{{O}_{3}}and\text{ }{{10}^{-6}}M\text{ }HCl\]
Correct Answer: C
Solution :
For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product. A precipitate of\[AgCl\]is formed when equal volumes of\[{{10}^{-5}}M\text{ }AgN{{O}_{3}}\] and\[{{10}^{-5}}M\text{ }HCl\]are mixed, because ionic product will be\[{{10}^{-9}}\]which is greater than\[{{K}_{sp}}({{10}^{-10}})\].
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