A) 1.0 mol
B) 0.20 mol
C) 0.40 mol
D) 0.80 mol
Correct Answer: B
Solution :
The electrode reaction is \[P{{t}^{4+}}+4{{e}^{-}}\xrightarrow[{}]{{}}Pt\] \[\therefore \]Quantity of charge required for reduction of 1 mole of \[P{{t}^{4+}}=4F\] or 4F electricity produces = 1 mole of \[P{{t}^{4+}}\] \[\therefore \]0.80 F electricity will produce \[=\frac{0.80}{4}=0.20\,mol\,of\,P{{t}^{4+}}\]
You need to login to perform this action.
You will be redirected in
3 sec
