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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    If in the reaction\[{{N}_{2}}{{O}_{4}}2NO_{2}^{-};x\] is that part of\[{{N}_{2}}{{O}_{4}}\]which dissociates, then the number of molecules at equilibrium will be

    A)  1                                            

    B)  3

    C)  \[(1+x)\]                            

    D)  \[{{(1+x)}^{2}}\]

    Correct Answer: C

    Solution :

                    \[{{N}_{2}}{{O}_{2}}2N{{O}_{2}}\] 1                              0 before dissociation \[1-x\]                  \[2x\]after dissociation Total number of moles at equilibrium \[=1-x\text{ }+2x=1+\text{ }x\]


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