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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    An aqueous solution containing 6.5 g of\[NaCl\] of 90 purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid\[NaOH\]. The volume of 1M acetic acid required to neutralise\[NaOH\] obtained above is

    A)  \[1000c{{m}^{3}}\]       

    B)  \[2000c{{m}^{3}}\]

    C)  \[100c{{m}^{3}}\]                           

    D)  \[200c{{m}^{3}}\]

    Correct Answer: C

    Solution :

                     Weight of pure \[NaCl=6.5\times 0.9=5.85\text{ }g\] Number of equivalence of\[NaCl=\frac{5.85}{58.5}=0.1\] Number of equivalence of\[NaOH\]obtained \[=0.1\] Volume of 1 M acetic acid required for the neutralisation of \[NaOH=\frac{0.1\times 1000}{1}=100\text{ }c{{m}^{3}}\]


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