question_answer

The hybridisation of the central atom in\[Br{{F}_{5}}\]molecule is

A)  \[s{{p}^{3}}\]                                   

B)  \[ds{{p}^{2}}\]   

C)  \[s{{p}^{3}}{{d}^{2}}\]                 

D)  \[{{d}^{3}}s{{p}^{3}}\]

Correct Answer: C

Solution :

                In\[Br{{F}_{5}},\]there are seven electrons in the valence shell of the central Br-atom. Five out of these are shared with fluorine atoms. Thus. there are five bond pairs and one lone pair. Hence, the hybridisation is\[s{{p}^{3}}{{d}^{2}}\]and shape is square pyramidal.