A) 387.5 dyne\[c{{m}^{-2}}\]
B) 328 dyne\[c{{m}^{-2}}\]
C) 250 dyne\[c{{m}^{-2}}\]
D) 428 dyne\[c{{m}^{-2}}\]
Correct Answer: A
Solution :
Shearing stress\[=\eta \times \]strain rate\[=\eta .\frac{dv}{dx}=15.5\times \frac{5}{0.2}=387.5dyne\text{ }c{{m}^{-2}}\]
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